![If `lambda_(Cu)` is the wavelength of `K_(alpha)` X-ray line of copper (atomic number `29`) - YouTube If `lambda_(Cu)` is the wavelength of `K_(alpha)` X-ray line of copper (atomic number `29`) - YouTube](https://i.ytimg.com/vi/Eo5lYTogdN0/maxresdefault.jpg)
If `lambda_(Cu)` is the wavelength of `K_(alpha)` X-ray line of copper (atomic number `29`) - YouTube
![Experimental setup of Cu-K-alpha source with two variants dedicated to:... | Download Scientific Diagram Experimental setup of Cu-K-alpha source with two variants dedicated to:... | Download Scientific Diagram](https://www.researchgate.net/publication/259412524/figure/fig1/AS:341308867661848@1458385783924/Experimental-setup-of-Cu-K-alpha-source-with-two-variants-dedicated-to-a-time-resolved.png)
Experimental setup of Cu-K-alpha source with two variants dedicated to:... | Download Scientific Diagram
![If lambda(Cu) is the wavelength of K(alpha) X-ray line of copper (atomic number 29) and lambda(Mo) is the wavelength of the K(alpha)X-ray line of molybdenum (atomic number 42),then the ratio lambda(Cu)//lambda(Mo) is If lambda(Cu) is the wavelength of K(alpha) X-ray line of copper (atomic number 29) and lambda(Mo) is the wavelength of the K(alpha)X-ray line of molybdenum (atomic number 42),then the ratio lambda(Cu)//lambda(Mo) is](https://d10lpgp6xz60nq.cloudfront.net/ss/web/400750.jpg)
If lambda(Cu) is the wavelength of K(alpha) X-ray line of copper (atomic number 29) and lambda(Mo) is the wavelength of the K(alpha)X-ray line of molybdenum (atomic number 42),then the ratio lambda(Cu)//lambda(Mo) is
![K(alpha) radiation of Mo (Z = 42) has a wavelength of 0.71Å. Calculate wavelength of the corresponding radiation of Cu (Z=29) K(alpha) radiation of Mo (Z = 42) has a wavelength of 0.71Å. Calculate wavelength of the corresponding radiation of Cu (Z=29)](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/415585498_web.png)
K(alpha) radiation of Mo (Z = 42) has a wavelength of 0.71Å. Calculate wavelength of the corresponding radiation of Cu (Z=29)
![quantum mechanics - Characteristic Radiation - $K_{\alpha}$, ... ; but no $K_{\gamma}$ - Physics Stack Exchange quantum mechanics - Characteristic Radiation - $K_{\alpha}$, ... ; but no $K_{\gamma}$ - Physics Stack Exchange](https://i.stack.imgur.com/YVySZ.png)